Kamis, 14 November 2013

KALKULUS (FUNGSI)

1. Diketahui f(x) = 2x-1, g(x) = 5-3x. Tentukanlah f o g (x)!
                f o g (x) = f (5-3x)
                                = 2 (5-3x) – 1
                                = 10 – 6x – 1
                                = 9 – 6x
                                = -6x + 9
2. Diketahui f(x) dan g(x) seperti nomor 1 dan h(x) = 2x.x, tentukanlah f o g o h (x)!
                f o g o h (x)         = f o g (2x.x)
                                                = f {5-3(2x.x)}
                                                = f {5-6x.x)
                                                = 2 (5-6x.x)-1
                                                = 10 – 12x.x – 1
                                                = 9 – 12x.x
                                                = -12x.x + 9
3. Dari soal nomor 2, tentukanlah f o g o h (-2)!
                f o g o h (-2)        = f o g (2x.x)
                                                = f {5 – 3(2x.x)}
                                                = f (5 – 6x.x)
                                                = 2 (5 – 6x.x) – 1
                                                = 10 – 12x.x – 1
                                                = 9 – 12x.x
                                                = 9 – 12(-2)(-2)
                                                = 9 – 12(4)
                                                = 9 – 48
                                                = - 39
4. Diketahui f(x) = 3x-2, g(x) = 6-6x dan h(x) = x.x. tentukanlah h o f o g (x)!
                h o f o g (x)         = h o f (6 – 6x)
                                                = h {3 (6 – 6x) – 2}
                                                = h ( 18 – 18x – 2)
                                                = h ( 16 – 18x)
                                                = (16 – 18x)(16 – 18x)
                                                = 256 – 288x – 288x + 324x.x
                                                = 256 – 576x + 324x.x
                                                = 324x.x – 576x + 256
5. Dari soal nomor 4, tentukanlah g o f o h (1)!
                g o f o h (1)         = g o f (x.x)
                                                = g {3 (x.x) – 2}
                                                = g (3x.x – 2)
                                                = 6 – 6(3x.x – 2)
                                                = 6 – 18x.x + 12
                                                = 18 – 18x.x
                                                = 18 – 18(1)(1)
                                                = 18 – 18

                                                = 0